Difference between revisions of "2024 AMC 8 Problems/Problem 6"
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P is greater than R | P is greater than R | ||
and R and P are the smallest two, therefore the order is R, P, S, Q | and R and P are the smallest two, therefore the order is R, P, S, Q | ||
| − | thus we get the answer | + | thus we get the answer (D) R, P, S, Q |
- U-King | - U-King | ||
Revision as of 21:24, 26 January 2024
Problem
Sergai skated around an ice rink, gliding along different paths. The gray lines in the figures below show four of the paths labeled P, Q, R, and S. What is the sorted order of the four paths from shortest to longest?
[DIAGRAM]
Solution 1
You can measure the lengths of the paths until you find a couple of guaranteed true inferred statements as such: Q is greater than S P is greater than R and R and P are the smallest two, therefore the order is R, P, S, Q thus we get the answer (D) R, P, S, Q
- U-King
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
