Difference between revisions of "2024 AMC 8 Problems/Problem 14"
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We can simply see that path <math>A \rightarrow X \rightarrow M \rightarrow Y \rightarrow C \rightarrow Z</math> will give us the smallest value. Adding, <math>5+2+6+5+10 = \boxed{28}</math>. This is nice as it’s also the smallest value, solidifying our answer. | We can simply see that path <math>A \rightarrow X \rightarrow M \rightarrow Y \rightarrow C \rightarrow Z</math> will give us the smallest value. Adding, <math>5+2+6+5+10 = \boxed{28}</math>. This is nice as it’s also the smallest value, solidifying our answer. | ||
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| + | ~MaxyMoosy | ||
==Video Solution 1 (easy to digest) by Power Solve== | ==Video Solution 1 (easy to digest) by Power Solve== | ||
Revision as of 21:00, 26 January 2024
Contents
Problem
The one-way routes connecting towns 
and 
are shown in the figure below(not drawn to scale).The distances in kilometers along each route are marked. Traveling along these routes, what is the shortest distance form A to Z in kilometers?
Solution 1
We can simply see that path 
will give us the smallest value. Adding, 
. This is nice as it’s also the smallest value, solidifying our answer.
~MaxyMoosy
Video Solution 1 (easy to digest) by Power Solve
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=RRTxlduaDs8
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 13 |
Followed by Problem 15 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
