Difference between revisions of "2024 AMC 8 Problems/Problem 7"
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<math>\textbf{(A) } 21 \qquad \textbf{(B) } 37 \qquad \textbf{(C) } 43 \qquad \textbf{(D) } 44 \qquad \textbf{(E) } 259</math> | <math>\textbf{(A) } 21 \qquad \textbf{(B) } 37 \qquad \textbf{(C) } 43 \qquad \textbf{(D) } 44 \qquad \textbf{(E) } 259</math> | ||
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| + | Note: This is not one of the AMC 8 2024 questions. Do not use this to cheat. | ||
==Solution 1== | ==Solution 1== | ||
Revision as of 13:46, 22 January 2024
Problem
A person is playing one turn in a card-based game. They can play Card A for 1 point, Card B for 2 points, and Card C for 3 points. If order of the cards doesn't matter, how many possible ways are there to play one turn with 20 points considering that that there is an unlimited amount of each card?
Note: This is not one of the AMC 8 2024 questions. Do not use this to cheat.
