Difference between revisions of "1997 AJHSME Problems/Problem 22"

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==Solution 1==
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The 2x2x2 cube of silver can be divided into <math>8</math> equal cubes that are 1x1x1.  Each smaller cube is worth <math>\frac{200}{8} = 25</math> dollars.
 
 
 
To create a 3x3x3 cube of silver, you need <math>27</math> of those 1x1x1 cubes.  The cost of those <math>27</math> cubes is <math>27 \cdot 25 = 675</math> dollars, which is answer <math>\boxed{E}</math>
 
  
 
==Solution 2==
 
==Solution 2==

Revision as of 13:24, 24 December 2023

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Solution 2

Since price is directly proportional to the amount (or volume) of silver, we must have a constant quotient.

Setting up a proportion:

$\frac{200}{2^3} = \frac{x}{3^3}$

$x = 200 \cdot \frac{3^3}{2^3} = 675$, which is answer $\boxed{E}$

See also

1997 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 21
Followed by
Problem 23
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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