Difference between revisions of "2023 AMC 8 Problems/Problem 19"

Revision as of 18:28, 22 December 2023

1 Problem
2 Solution 1
3 Solution 2
4 Video Solution by Math-X (Quick and Simple Under 30 seconds)
5 Video Solution (CREATIVE THINKING!!!)
6 Video Solution by OmegaLearn (Using Similar Triangles)
7 Animated Video Solution
8 Video Solution by SpreadTheMathLove using Area-Similarity Relationship
9 Video Solution by Magic Square
10 Video Solution by Interstigation
11 Video Solution by WhyMath
12 Video Solution by harungurcan
13 See Also

Problem

An equilateral triangle is placed inside a larger equilateral triangle so that the region between them can be divided into three congruent trapezoids, as shown below. The side length of the inner triangle is $\frac23$ the side length of the larger triangle. What is the ratio of the area of one trapezoid to the area of the inner triangle?

$[asy] // Diagram by TheMathGuyd pair A,B,C; A=(0,1); B=(sqrt(3)/2,-1/2); C=-conj(B); fill(2B--3B--3C--2C--cycle,grey); dot(3A); dot(3B); dot(3C); dot(2A); dot(2B); dot(2C); draw(2A--2B--2C--cycle); draw(3A--3B--3C--cycle); draw(2A--3A); draw(2B--3B); draw(2C--3C); [/asy]$

$\textbf{(A) } 1 : 3 \qquad \textbf{(B) } 3 : 8 \qquad \textbf{(C) } 5 : 12 \qquad \textbf{(D) } 7 : 16 \qquad \textbf{(E) } 4 : 9$

Solution 1

All equilateral triangles are similar. For the outer equilateral triangle to the inner equilateral triangle, since their side-length ratio is $\frac32,$ their area ratio is $\left(\frac32\right)^2=\frac94.$ It follows that the area ratio of three trapezoids to the inner equilateral triangle is $\frac94-1=\frac54,$ so the area ratio of one trapezoid to the inner equilateral triangle is $\frac54\cdot\frac13=\frac{5}{12}=\boxed{\textbf{(C) } 5 : 12}.$ ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM

Solution 2

Subtracting the larger equilateral triangle from the smaller one yields the sum of the three trapezoids. Since the ratio of the side lengths of the larger to the smaller one is $3:2$ , we can set the side lengths as $3$ and $2$ , respectively. So, the sum of the trapezoids is $\frac{9\sqrt{3}}{4}-\frac{4\sqrt{3}}{4}=\frac{5}{4}\sqrt{3}$ . We are also told that the three trapezoids are congruent, thus the area of each of them is $\frac{1}{3} \cdot \frac{5}{4}\sqrt{3}=\frac{5}{12}\sqrt{3}$ . Hence, the ratio is $\frac{\frac{5}{12}\sqrt{3}}{\sqrt{3}}=\frac{5}{12}=\boxed{\textbf{(C) } 5 : 12}$ .

~MrThinker

Video Solution by Math-X (Quick and Simple Under 30 seconds)

https://youtu.be/Ku_c1YHnLt0?si=AtiMigHKcdyC8nw9&t=4074 ~Math-X

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/u0Qa3A3jFFU

~Education, the Study of Everything

Video Solution by OmegaLearn (Using Similar Triangles)

https://youtu.be/bGN-uBsVm0E

Animated Video Solution

https://youtu.be/Xq4LdJJtbDk

Video Solution by SpreadTheMathLove using Area-Similarity Relationship

https://www.youtube.com/watch?v=92hAg3JjqZI

~Star League (https://starleague.us)

Video Solution by Magic Square

https://youtu.be/-N46BeEKaCQ?t=3360

Video Solution by Interstigation

https://youtu.be/DBqko2xATxs&t=24

Video Solution by WhyMath

https://youtu.be/gjc3Dslaimg

~savannahsolver

Video Solution by harungurcan

https://www.youtube.com/watch?v=Ki4tPSGAapU&t=350s

~harungurcan

@@ Line 56: / Line 56: @@
 https://youtu.be/-N46BeEKaCQ?t=3360
 ==Video Solution by Interstigation==
-https://youtu.be/DBqko2xATxs&t=2447
+https://youtu.be/DBqko2xATxs&t=24
 ==Video Solution by WhyMath==

2023 AMC 8 (Problems • Answer Key • Resources)
Preceded by Problem 18	Followed by Problem 20
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