Difference between revisions of "1992 OIM Problems/Problem 3"
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~translated into English by Tomas Diaz. ~orders@tomasdiaz.com | ~translated into English by Tomas Diaz. ~orders@tomasdiaz.com | ||
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== Solution == | == Solution == | ||
| + | * Note. I actually competed at this event in Venezuela when I was in High School representing Puerto Rico. I got full points for part a and partial points for part b. I don't remember what I did. I will try to write a solution for this one later. | ||
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{{solution}} | {{solution}} | ||
== See also == | == See also == | ||
https://www.oma.org.ar/enunciados/ibe7.htm | https://www.oma.org.ar/enunciados/ibe7.htm | ||
Revision as of 17:20, 14 December 2023
Problem
In an equilateral triangle 
whose side has length 2, the circle 
is inscribed.
a. Show that for every point 
of , the sum of the squares of its distances to the vertices 
, 
and 
is 5.
b. Show that for every point in it is possible to construct a triangle whose sides have the lengths of the segments 
, 
and 
, and that its area is:
![\[\frac{\sqrt{3}}{4}\]](http://latex.artofproblemsolving.com/8/c/e/8ce2da9a94e15e4b68d0b8ca5b86bfff6a90f92c.png)
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
Solution
- Note. I actually competed at this event in Venezuela when I was in High School representing Puerto Rico. I got full points for part a and partial points for part b. I don't remember what I did. I will try to write a solution for this one later.
This problem needs a solution. If you have a solution for it, please help us out by adding it.
