Difference between revisions of "2023 AMC 10B Problems/Problem 8"
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==Solution== | ==Solution== | ||
− | <math>2022^{2023} + 2023^{2022} \equiv 2^3 + 3^2 \equiv 17 \equiv 7</math> (mod 10). <math>\boxed{\text{ | + | <math>2022^{2023} + 2023^{2022} \equiv 2^3 + 3^2 \equiv 17 \equiv 7</math> (mod 10). <math>\boxed{\text{A}}</math> |
~andliu766 | ~andliu766 |
Revision as of 15:31, 15 November 2023
What is the units digit of ?
Solution
(mod 10). ~andliu766