Difference between revisions of "Totally ordered set"

 
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Note that it is possible to impose a total ordering on any set.  For example, the [[lexicographic ordering]] on the [[complex number]]s, where we say <math>a + bi > c + di</math> if <math>a > c</math> or if <math>a = c</math> and <math>b > d</math>, is a total ordering, but it is not a "natural" ordering of this set.  In particular, it behaves very poorly with respect to arithmetic operations on <math>\mathbb C</math>.
 
Note that it is possible to impose a total ordering on any set.  For example, the [[lexicographic ordering]] on the [[complex number]]s, where we say <math>a + bi > c + di</math> if <math>a > c</math> or if <math>a = c</math> and <math>b > d</math>, is a total ordering, but it is not a "natural" ordering of this set.  In particular, it behaves very poorly with respect to arithmetic operations on <math>\mathbb C</math>.
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== See also ==
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* [[Order relation]]
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* [[Binary relation]]
  
 
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[[Category:Set theory]]

Latest revision as of 11:52, 25 November 2007

A totally ordered set is a partially ordered set in which every two elements are comparable. Thus, the standard ordering on the real numbers $\mathbb{R}$ or the integers $\mathbb Z$ is a total ordering, but if we order the subsets of the set $\{1, 2, 3\}$ by inclusion (the boolean lattice on a set of size 3), we don't get a total order because $\{1, 2\}$ and $\{3\}$ are incomparable (there are no inclusion relations between them).

Note that it is possible to impose a total ordering on any set. For example, the lexicographic ordering on the complex numbers, where we say $a + bi > c + di$ if $a > c$ or if $a = c$ and $b > d$, is a total ordering, but it is not a "natural" ordering of this set. In particular, it behaves very poorly with respect to arithmetic operations on $\mathbb C$.

See also

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