Difference between revisions of "2022 AMC 8 Problems/Problem 17"

(Video Solution by OmegaLearn)
(Video Solution (CREATIVE THINKING!!!))
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~wamofan
 
~wamofan
==Video Solution (CREATIVE THINKING!!!)==
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==Video Solution (🚀Under 2 min🚀)==
 
https://youtu.be/qOBzhBx8uw4
 
https://youtu.be/qOBzhBx8uw4
  
 
~Education, the Study of Everything
 
~Education, the Study of Everything
 
 
  
 
== Video Solution==
 
== Video Solution==

Revision as of 23:31, 14 August 2023

Problem

If $n$ is an even positive integer, the $\emph{double factorial}$ notation $n!!$ represents the product of all the even integers from $2$ to $n$. For example, $8!! = 2 \cdot 4 \cdot 6 \cdot 8$. What is the units digit of the following sum? \[2!! + 4!! + 6!! + \cdots + 2018!! + 2020!! + 2022!!\]

$\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8$

Solution

Notice that once $n>8,$ the units digit of $n!!$ will be $0$ because there will be a factor of $10.$ Thus, we only need to calculate the units digit of \[2!!+4!!+6!!+8!! = 2+8+48+48\cdot8.\] We only care about units digits, so we have $2+8+8+8\cdot8,$ which has the same units digit as $2+8+8+4.$ The answer is $\boxed{\textbf{(B) } 2}.$

~wamofan

Video Solution (🚀Under 2 min🚀)

https://youtu.be/qOBzhBx8uw4

~Education, the Study of Everything

Video Solution

https://youtu.be/wp9tOyJ3YQY?t=146

Video Solution

https://youtu.be/Ij9pAy6tQSg?t=1461

~Interstigation

https://www.youtube.com/watch?v=FTVLuv_n9bY

~Ismail.Maths

Video Solution

https://youtu.be/hs6y4PWnoWg?t=80

~STEMbreezy

Video Solution

https://youtu.be/BbGqQaqE2rM

~savannahsolver

See Also

2022 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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