Difference between revisions of "2023 AMC 8 Problems/Problem 3"
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By substitution, we have | By substitution, we have | ||
<cmath>\begin{align*} | <cmath>\begin{align*} | ||
| − | (\text{wind chill}) &= 36 - 0.7 \times 18 \\ | + | (\text{wind chill}) &= (\text{air temperature}) - 0.7 \times (\text{wind speed}) \\ |
| + | &= 36 - 0.7 \times 18 \\ | ||
&= 36 - 12.6 \\ | &= 36 - 12.6 \\ | ||
&= 23.4 \\ | &= 23.4 \\ | ||
&\approx \boxed{\textbf{(B)}\ 23}. | &\approx \boxed{\textbf{(B)}\ 23}. | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
| − | ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM | + | ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, lpieleanu, MRENTHUSIASM, |
==Video Solution by Magic Square== | ==Video Solution by Magic Square== | ||
Revision as of 10:13, 6 May 2023
Contents
Problem
Wind chill is a measure of how cold people feel when exposed to wind outside. A good estimate for wind chill can be found using this calculation
![\[(\text{wind chill}) = (\text{air temperature}) - 0.7 \times (\text{wind speed}),\]](http://latex.artofproblemsolving.com/6/6/8/66810c2843261301faabc4441239f8fa51b1f231.png)
where temperature is measured in degrees Fahrenheit 
and the wind speed is measured in miles per hour (mph). Suppose the air temperature is 
and the wind speed is 
mph. Which of the following is closest to the approximate wind chill?
Solution
By substitution, we have
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, lpieleanu, MRENTHUSIASM,
Video Solution by Magic Square
https://youtu.be/-N46BeEKaCQ?t=5606
Video Solution by SpreadTheMathLove
https://www.youtube.com/watch?v=EcrktBc8zrM
Video Solution by Interstigation
https://youtu.be/1bA7fD7Lg54?t=113
(Creative Thinking) Video Solution
~Education the Study of everything
Video Solution by WhyMath
~savannahsolver
Video Solution by harungurcan
https://www.youtube.com/watch?v=35BW7bsm_Cg&t=230s
~harungurcan
See Also
| 2023 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
