Difference between revisions of "Excircle"
(→Intermediate: link) |
(new problems) |
||
Line 11: | Line 11: | ||
==Problems== | ==Problems== | ||
===Introductory=== | ===Introductory=== | ||
+ | *Let <math>E,F</math> be the feet of the perpendiculars from the vertices <math>B,C</math> of triangle <math>\triangle ABC</math>. Let <math>O</math> be the circumcenter <math>\triangle ABC</math>. Prove that | ||
+ | \[ | ||
+ | OA \perp FE . | ||
+ | \] | ||
+ | (<url>viewtopic.php?search_id=1224374835&t=45647 Source</url>) | ||
===Intermediate=== | ===Intermediate=== | ||
*In triangle <math>ABC</math>, let the <math>A</math>-excircle touch <math>BC</math> at <math>D</math>. Let the <math>B</math>-excircle of triangle <math>ABD</math> touch <math>AD</math> at <math>P</math> and let the <math>C</math>-excircle of triangle <math>ACD</math> touch <math>AD</math> at <math>Q</math>. Is <math>\angle P\cong\angle Q</math> true for all triangles <math>ABC</math>? (<url>viewtopic.php?t=167688 Source</url>) | *In triangle <math>ABC</math>, let the <math>A</math>-excircle touch <math>BC</math> at <math>D</math>. Let the <math>B</math>-excircle of triangle <math>ABD</math> touch <math>AD</math> at <math>P</math> and let the <math>C</math>-excircle of triangle <math>ACD</math> touch <math>AD</math> at <math>Q</math>. Is <math>\angle P\cong\angle Q</math> true for all triangles <math>ABC</math>? (<url>viewtopic.php?t=167688 Source</url>) | ||
Line 17: | Line 22: | ||
*<math>\triangle ABC</math> is a triangle. Take points <math>D, E, F</math> on the perpendicular bisectors of <math>BC, CA, AB</math> respectively. Show that the lines through <math>A, B, C</math> perpendicular to <math>EF, FD, DE</math> respectively are concurrent. ([[1997 USAMO Problems/Problem 2|Source]]) | *<math>\triangle ABC</math> is a triangle. Take points <math>D, E, F</math> on the perpendicular bisectors of <math>BC, CA, AB</math> respectively. Show that the lines through <math>A, B, C</math> perpendicular to <math>EF, FD, DE</math> respectively are concurrent. ([[1997 USAMO Problems/Problem 2|Source]]) | ||
*Let <math>ABC</math> be a triangle with circumcircle <math>\omega.</math> Point <math>D</math> lies on side <math>BC</math> such that <math>\angle BAD = \angle CAD.</math> Let <math>I_{A}</math> denote the excenter of triangle <math>ABC</math> opposite <math>A,</math> and let <math>\omega_{A}</math> denote the circle with <math>AI_{A}</math> as its diameter. Circles <math>\omega</math> and <math>\omega_{A}</math> meet at <math>P</math> other than <math>A.</math> The circumcle of triangle <math>APD</math> meet line <math>BC</math> again at <math>Q\, (</math>other than <math>D).</math> Prove that <math>Q</math> lies on the excircle of triangle <math>ABC</math> opposite <math>A</math>. (Source: Problem 13.2 - MOSP 2007) | *Let <math>ABC</math> be a triangle with circumcircle <math>\omega.</math> Point <math>D</math> lies on side <math>BC</math> such that <math>\angle BAD = \angle CAD.</math> Let <math>I_{A}</math> denote the excenter of triangle <math>ABC</math> opposite <math>A,</math> and let <math>\omega_{A}</math> denote the circle with <math>AI_{A}</math> as its diameter. Circles <math>\omega</math> and <math>\omega_{A}</math> meet at <math>P</math> other than <math>A.</math> The circumcle of triangle <math>APD</math> meet line <math>BC</math> again at <math>Q\, (</math>other than <math>D).</math> Prove that <math>Q</math> lies on the excircle of triangle <math>ABC</math> opposite <math>A</math>. (Source: Problem 13.2 - MOSP 2007) | ||
+ | *Let <math>ABCD </math> be a parallelogram. A variable line <math> \ell </math> passing through the point <math>A </math> intersects the rays <math>BC </math> and <math>DC </math> at points <math>X </math> and <math>Y </math>, respectively. Let <math>K </math> and <math>L </math> be the centres of the excircles of triangles <math>ABX </math> and <math>ADY </math>, touching the sides <math>BX </math> and <math>DY </math>, respectively. Prove that the size of angle <math>KCL </math> does not depend on the choice of <math> \ell </math>. ([[2005 IMO Shortlist Problems/G3|Source]]) | ||
==See also== | ==See also== |
Revision as of 09:28, 5 November 2007
An excircle is a circle tangent to the extensions of two sides of a triangle and the third side.
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
Contents
Properties
For any triangle, there are three unique excircles. This follows from the fact that there is one, if any, circle such that three given distinct lines are tangent to it.
Related Formulas
- If the circle is tangent to side of the circle, the radius is , where is the triangle's area, and are side lengths.
- If the circle is tangent to side of the circle, the radius is , where is the triangle's area, and are side lengths.
- If the circle is tangent to side of the circle, the radius is , where is the triangle's area, and are side lengths.
Problems
Introductory
- Let be the feet of the perpendiculars from the vertices of triangle . Let be the circumcenter . Prove that
\[ OA \perp FE . \] (<url>viewtopic.php?search_id=1224374835&t=45647 Source</url>)
Intermediate
- In triangle , let the -excircle touch at . Let the -excircle of triangle touch at and let the -excircle of triangle touch at . Is true for all triangles ? (<url>viewtopic.php?t=167688 Source</url>)
Olympiad
- is a triangle. Take points on the perpendicular bisectors of respectively. Show that the lines through perpendicular to respectively are concurrent. (Source)
- Let be a triangle with circumcircle Point lies on side such that Let denote the excenter of triangle opposite and let denote the circle with as its diameter. Circles and meet at other than The circumcle of triangle meet line again at other than Prove that lies on the excircle of triangle opposite . (Source: Problem 13.2 - MOSP 2007)
- Let be a parallelogram. A variable line passing through the point intersects the rays and at points and , respectively. Let and be the centres of the excircles of triangles and , touching the sides and , respectively. Prove that the size of angle does not depend on the choice of . (Source)