Difference between revisions of "2021 CMC 12A Problems/Problem 4"
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{{duplicate|[[2021 CMC 12A Problems | 2021 CMC 12A #4]] and [[2021 CMC 10A Problems | 2021 CMC 10A #5]]}} | {{duplicate|[[2021 CMC 12A Problems | 2021 CMC 12A #4]] and [[2021 CMC 10A Problems | 2021 CMC 10A #5]]}} | ||
==Problem== | ==Problem== | ||
− | There exists a positive integer <math>N</math> such that <cmath>\frac{\tfrac{1}{999}+\tfrac{1}{1001}}{2}=\frac{1}{N}.</cmath> What is the sum of the digits of <math>N</math>? | + | There exists a positive integer <math>N</math> such that <cmath>\frac{\tfrac{1}{999}+\tfrac{1}{1001}}{2}=\frac{1}{1000}+\frac{1}{N}.</cmath> What is the sum of the digits of <math>N</math>? |
<math>\textbf{(A) } 36\qquad\textbf{(B) } 45\qquad\textbf{(C) } 54\qquad\textbf{(D) } 63\qquad\textbf{(E) } 72\qquad</math> | <math>\textbf{(A) } 36\qquad\textbf{(B) } 45\qquad\textbf{(C) } 54\qquad\textbf{(D) } 63\qquad\textbf{(E) } 72\qquad</math> |
Latest revision as of 23:41, 24 March 2023
- The following problem is from both the 2021 CMC 12A #4 and 2021 CMC 10A #5, so both problems redirect to this page.
Contents
Problem
There exists a positive integer such that What is the sum of the digits of ?
Solution
Let . Then or , so whose digits sum to .
Video Solution
~Punxsutawney Phil
See also
2021 CMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 3 |
Followed by Problem 5 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All CMC 12 Problems and Solutions |
2021 CMC 10A (Problems • Answer Key • Resources) | |
Preceded by Problem 4 |
Followed by Problem 6 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All CMC 10 Problems and Solutions |
The problems on this page are copyrighted by the MAC's Christmas Mathematics Competitions.