Difference between revisions of "2023 AMC 8 Problems/Problem 17"
Themathguyd (talk | contribs) (A carefully constructed Asymptote diagram has been added.) |
(bruh whoever didn't add the choices bruh) |
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label("$1$",trf*CD-2DA); | label("$1$",trf*CD-2DA); | ||
</asy> | </asy> | ||
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+ | <math>\textbf{(A)}\ 1 \qquad \textbf{(B)}\ 2 \qquad \textbf{(C)}\ 3 \qquad \textbf{(D)}\ 4 \qquad \textbf{(E)}\ 5</math> | ||
==Solution (Intuition)== | ==Solution (Intuition)== |
Revision as of 14:38, 25 January 2023
Contents
Problem
A regular octahedron has eight equilateral triangle faces with four faces meeting at each vertex. Jun will make the regular octahedrons shown on the right by folding the piece of paper shown on the left. Which numbered face will end up to the right of ?
Solution (Intuition)
The answer is Use intuition to bring it down to guesses or and guess from there or you could actually fold the paper. -apex304
Animated Video Solution
~Star League (https://starleague.us)
Video Solution by OmegaLearn (Using 3D Visualization)
Video Solution by Magic Square
https://youtu.be/-N46BeEKaCQ?t=3789
See Also
2023 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.