Difference between revisions of "2009 AMC 8 Problems/Problem 1"
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~John0412 | ~John0412 | ||
| − | + | ===Solution 2=== | |
| + | You can work backwards and add 3 apples that she gave to Cassie to the 4 she currently has, which results in 7, and then multiply by 2 since she gave half the apples to Ann, resulting in <math> \qquad\textbf{(E)}\ 14 </math>.<br. | ||
| + | ~Anabel.disher | ||
==Video Solution== | ==Video Solution== | ||
https://www.youtube.com/watch?v=USVVURBLaAc | https://www.youtube.com/watch?v=USVVURBLaAc | ||
Revision as of 16:05, 24 October 2022
Problem
Bridget bought a bag of apples at the grocery store. She gave half of the apples to Ann. Then she gave Cassie 3 apples, keeping 4 apples for herself. How many apples did Bridget buy?
Solution
If we set up an equation, we find out x=(3+4)*2 because 3 apples were left after giving half, then four away. We can simplify the equations to x=7*2=14. The answer is (E) 14.
~John0412
Solution 2
You can work backwards and add 3 apples that she gave to Cassie to the 4 she currently has, which results in 7, and then multiply by 2 since she gave half the apples to Ann, resulting in 
.<br.
~Anabel.disher
Video Solution
https://www.youtube.com/watch?v=USVVURBLaAc
See Also
| 2009 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
