Difference between revisions of "User:Temperal/The Problem Solver's Resource Tips and Tricks"
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<math>\Rightarrow 2(n_1+n_2+n_3+n_4)=94</math> | <math>\Rightarrow 2(n_1+n_2+n_3+n_4)=94</math> | ||
− | <math>\Rightarrow n_1+n_2+n_3+n_4=47 | + | <math>\Rightarrow n_1+n_2+n_3+n_4=47</math> |
− | Binomial coefficients will yield the answer of < | + | Binomial coefficients will yield the answer of <math>\boxed{19600}</math>. |
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Revision as of 11:44, 13 October 2007
Other Tips and TricksThis is a collection of general techniques for solving problems.
Example Problem Number 1If and , find . SolutionLet , . Thus, , , so , hence , which turns out to be . This technique can also be used to solve quadratics of high degrees, i.e. ; let , and solve from there.
Example Problem Number 2How many quadruples such that where are all odd? SolutionSince they're odd, can each be expressed as for some positive integer (or zero) . Thus:
Binomial coefficients will yield the answer of .
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