Difference between revisions of "User talk:Temperal/The Problem Solver's Resource Competition"
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== Problem 2 == | == Problem 2 == | ||
I don't think the question is worded correctly. I haven't actually thought much about it yet, but a variable <math>o</math> is introduced and not used, and the <math>l</math> simply disappears from the ending condition (but the condition given is symmetric). And there are simple counter-proofs, let <math>p = 0.1</math> or some other value close to 0, and then it quickly becomes apparent that the entire denominator will approach <math>0</math>, and the inequality will be false. <font style="font-family:Georgia,sans-serif">[[User:Azjps|Azjps]] ([[User talk:Azjps|<font color="green">talk</font>]])</font> 21:49, 10 October 2007 (EDT) | I don't think the question is worded correctly. I haven't actually thought much about it yet, but a variable <math>o</math> is introduced and not used, and the <math>l</math> simply disappears from the ending condition (but the condition given is symmetric). And there are simple counter-proofs, let <math>p = 0.1</math> or some other value close to 0, and then it quickly becomes apparent that the entire denominator will approach <math>0</math>, and the inequality will be false. <font style="font-family:Georgia,sans-serif">[[User:Azjps|Azjps]] ([[User talk:Azjps|<font color="green">talk</font>]])</font> 21:49, 10 October 2007 (EDT) | ||
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| + | :Random counter-example: <math>p = l = m = 0.1</math>, <math>k = 0.299833</math>, <math>n = 0.172916</math>. Then the fraction becomes <math>111.4</math>. | ||
| + | :And problem 3, the same equation is given for both circles. I'm assuming you meant <math>9</math> for one of the radii? <font style="font-family:Georgia,sans-serif">[[User:Azjps|Azjps]] ([[User talk:Azjps|<font color="green">talk</font>]])</font> 18:33, 12 October 2007 (EDT) | ||
Revision as of 17:33, 12 October 2007
Problem 2
I don't think the question is worded correctly. I haven't actually thought much about it yet, but a variable 
is introduced and not used, and the 
simply disappears from the ending condition (but the condition given is symmetric). And there are simple counter-proofs, let 
or some other value close to 0, and then it quickly becomes apparent that the entire denominator will approach 
, and the inequality will be false. Azjps (talk) 21:49, 10 October 2007 (EDT)
, 
, 
. Then the fraction becomes 
.
for one of the radii? 
