Difference between revisions of "User:Temperal/The Problem Solver's Resource Tips and Tricks"
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Let <math>X = \tan x</math>, <math>Y = \tan y</math>. Thus, <math>X + Y = 25</math>, <math>\frac{1}{X} + \frac{1}{Y} = 30</math>, so <math>XY = \frac{5}{6}</math>, hence <math>\tan(x+y)=\frac{X+Y}{1-XY}</math>, which turns out to be <math>\boxed{150}</math>. | Let <math>X = \tan x</math>, <math>Y = \tan y</math>. Thus, <math>X + Y = 25</math>, <math>\frac{1}{X} + \frac{1}{Y} = 30</math>, so <math>XY = \frac{5}{6}</math>, hence <math>\tan(x+y)=\frac{X+Y}{1-XY}</math>, which turns out to be <math>\boxed{150}</math>. | ||
− | This technique can also be used to solve quadratics of high degrees, i.e. <math>x^16+x^4+6=0</math>; let <math>y=x^4</math>, and solve from there. | + | This technique can also be used to solve quadratics of high degrees, i.e. <math>x^{16}+x^4+6=0</math>; let <math>y=x^4</math>, and solve from there. |
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*Remember the special properties of odd numbers: For any odd number <math>o</math>, <math>o=2n-1</math> for some integer <math>n</math>, and <math>o=a^2-(a-1)^2</math> for some positive integer <math>a</math>. | *Remember the special properties of odd numbers: For any odd number <math>o</math>, <math>o=2n-1</math> for some integer <math>n</math>, and <math>o=a^2-(a-1)^2</math> for some positive integer <math>a</math>. | ||
− | *The | + | *The AM-GM and Trivial inequalities are more useful than you might imagine! |
*Memorize, memorize, memorize the following things: | *Memorize, memorize, memorize the following things: | ||
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#Integrals and derivatives, especially integrals. | #Integrals and derivatives, especially integrals. | ||
− | *Test your skills on [ | + | *Test your skills on practice [[AIME]]s (<url>resources.php more resources</url>) often! |
[[User:Temperal/The Problem Solver's Resource|Back to Introduction]] | [[User:Temperal/The Problem Solver's Resource|Back to Introduction]] | ||
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Revision as of 20:15, 10 October 2007
Other Tips and TricksThis is a collection of general techniques for solving problems.
Example Problem Number 1If and , find . SolutionLet , . Thus, , , so , hence , which turns out to be . This technique can also be used to solve quadratics of high degrees, i.e. ; let , and solve from there.
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