Difference between revisions of "1997 PMWC Problems/Problem I11"

Line 14: Line 14:
  
 
<math>w=30</math>
 
<math>w=30</math>
 +
 +
<math>l=45</math>
  
 
The perimeter of the big rectangle is
 
The perimeter of the big rectangle is
  
<math>2(w+l)+3w=330</math>
+
<math>2(w+l)+6w=330</math>

Revision as of 17:38, 8 October 2007

Problem

A rectangle ABCD is made up of five small congruent rectangles as shown in the given figure. Find the perimeter, in cm, of ABCD if its area is $6750 cm^2$. ABCD.gif

Solution

Let l and w be the length, and width, respectively, of one of the little rectangles.

$3w=2l$

$l=\dfrac{3}{2}w$

$6750=\dfrac{15}{2}w^2$

$w=30$

$l=45$

The perimeter of the big rectangle is

$2(w+l)+6w=330$