Difference between revisions of "2013 AMC 8 Problems/Problem 2"

(Solution)
Line 1: Line 1:
 
==Problem==
 
==Problem==
A sign at the fish market says, "50% off, today only: half-pound packages for just $3 per package." What is the regular price for a full pound of fish, in dollars?
+
A sign at the fish market says, "50% off, today only: half-pound packages for just \$3 per package." What is the regular price for a full pound of fish, in dollars?
  
 
<math>\textbf{(A)}\ 6 \qquad \textbf{(B)}\ 9 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 12 \qquad \textbf{(E)}\ 15</math>
 
<math>\textbf{(A)}\ 6 \qquad \textbf{(B)}\ 9 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 12 \qquad \textbf{(E)}\ 15</math>
  
 
==Solution==
 
==Solution==
The 50% off price of half a pound of fish is &#036;3, so the 100%, or the regular price, of a half pound of fish is &#036;6. Consequently, if half a pound of fish costs &#036;6, then a whole pound of fish is <math>\boxed{\textbf{(D)}\ 12}</math> dollars.
+
The 50% off price of half a pound of fish is \$3, so the 100%, or the regular price, of a half pound of fish is \$6. Consequently, if half a pound of fish costs \$6, then a whole pound of fish is <math>\boxed{\textbf{(D)}\ 12}</math> dollars.
 +
 
 +
==Video Solution==
 +
https://youtu.be/om14Kv2jCck ~savannahsolver
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2013|num-b=1|num-a=3}}
 
{{AMC8 box|year=2013|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 16:53, 5 May 2022

Problem

A sign at the fish market says, "50% off, today only: half-pound packages for just $3 per package." What is the regular price for a full pound of fish, in dollars?

$\textbf{(A)}\ 6 \qquad \textbf{(B)}\ 9 \qquad \textbf{(C)}\ 10 \qquad \textbf{(D)}\ 12 \qquad \textbf{(E)}\ 15$

Solution

The 50% off price of half a pound of fish is $3, so the 100%, or the regular price, of a half pound of fish is $6. Consequently, if half a pound of fish costs $6, then a whole pound of fish is $\boxed{\textbf{(D)}\ 12}$ dollars.

Video Solution

https://youtu.be/om14Kv2jCck ~savannahsolver

See Also

2013 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png