Difference between revisions of "2021 Fall AMC 10B Problems/Problem 1"
m (→Solution 1) |
|||
| Line 12: | Line 12: | ||
~kingofpineapplz | ~kingofpineapplz | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC10 box|year=2021 Fall|ab=A|before=First Problem|num-a=2}} | ||
| + | {{MAA Notice}} | ||
Revision as of 21:24, 22 November 2021
Problem
What is the value of 
Solution 1
We see that 
and 
each appear in the ones, tens, hundreds, and thousands digit exactly once. Since 
, we find that the sum is equal to ![\[10\cdot(1+10+100+1000)=\boxed{(\textbf{E})11,110}.\]](http://latex.artofproblemsolving.com/1/3/7/137d953cbcd2b520d1a0ccf3a8e5dfebcdf71f8f.png)
Note: it is equally valid to manually add all 4 numbers together to get the answer.
~kingofpineapplz
See Also
| 2021 Fall AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
