Difference between revisions of "1964 AHSME Problems/Problem 39"
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We know that in a <math>\triangle DEF</math>, if <math>\angle D \le \angle E</math> then <math>EF \le DF</math>, we can use this fact in the different triangles to form inequalities, and then add the inequalities. | We know that in a <math>\triangle DEF</math>, if <math>\angle D \le \angle E</math> then <math>EF \le DF</math>, we can use this fact in the different triangles to form inequalities, and then add the inequalities. | ||
− | In <math>\triangle ABC</math>, since <math>c \le b \le </math>, we have <math>\angle C \le \angle B \le \angle A</math> by the above argument. | + | In <math>\triangle ABC</math>, since <math>c \le b \le a</math>, we have <math>\angle C \le \angle B \le \angle A</math> by the above argument. |
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+ | Now, <math>\angle AXC \ge \B \ge \angle C</math>, hence we have <math>AC > AX \implies b > AX</math> | ||
==See Also== | ==See Also== |
Revision as of 00:45, 18 September 2021
Problem
The magnitudes of the sides of triangle are , , and , as shown, with . Through interior point and the vertices , , , lines are drawn meeting the opposite sides in , , , respectively. Let . Then, for all positions of point , is less than:
Solution
We know that in a , if then , we can use this fact in the different triangles to form inequalities, and then add the inequalities.
In , since , we have by the above argument.
Now, $\angle AXC \ge \B \ge \angle C$ (Error compiling LaTeX. Unknown error_msg), hence we have
See Also
1964 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 38 |
Followed by Problem 40 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |
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