Difference between revisions of "1965 AHSME Problems/Problem 3"
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== Solution == | == Solution == | ||
| − | Let us recall <math>PEMDAS</math>. We realize that we have to calculate the exponent first. <math>(-2)^{-2}=\frac{1}{(-2)^2}=\frac{1}{4}</math> When we substitute, we get <math>81^\ | + | Let us recall <math>\text{PEMDAS}</math>. We realize that we have to calculate the exponent first. <math>(-2)^{-2}=\frac{1}{(-2)^2}=\frac{1}{4}</math> When we substitute, we get <math>81^\dfrac{1}{4}=\sqrt[4]{81}=\boxed{\textbf{(C) }3}</math>. |
~Mathfun1000 (Explaining clearly) | ~Mathfun1000 (Explaining clearly) | ||
Revision as of 08:06, 18 August 2021
Problem
The expression 
has the same value as:
Solution
Let us recall 
. We realize that we have to calculate the exponent first. 
When we substitute, we get $81^\dfrac{1}{4}=\sqrt[4]{81}=\boxed{\textbf{(C) }3}$ (Error compiling LaTeX. Unknown error_msg).
~Mathfun1000 (Explaining clearly)
