Difference between revisions of "2007 AMC 12A Problems/Problem 8"

 
(Fine, leave me to draw the diagram and an incorrect answer ;))
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==Problem==
 
==Problem==
A star-polygon is drawn on a clock face by drawing a chord from each number to the fifth number counted clockwise from that number. That is, chords are drawn from 12 to 5, from 5 to 10, from 10 to 3, and so on, ending back at 12. What is the degree measure of the angle at each vertex in the star polygon?
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A star-[[polygon]] is drawn on a clock face by drawing a [[chord]] from each number to the fifth number counted clockwise from that number. That is, chords are drawn from 12 to 5, from 5 to 10, from 10 to 3, and so on, ending back at 12. What is the degree measure of the [[angle]] at each [[vertex]] in the star polygon?
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<math>\mathrm{(A)}\ 20\qquad \mathrm{(B)}\ 24\qquad \mathrm{(C)}\ 30\qquad \mathrm{(D)}\ 36\qquad \mathrm{(E)}\ 60</math>
  
 
==Solution==
 
==Solution==
I leave it to you to draw your own diagram.
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[[Image:2007_AMC12A-8.png]]
* We look at 6 o'clock. It subtends 1/6 of the circle, or 60 degrees. Therefore, the angle from the vertex measures 60 degrees. The same hold true for all of the other vertices.
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We look at the angle between 12, 5, and 10. It subtends <math>\displaystyle \frac 16</math> of the circle, or <math>60</math> degrees (or you can see that the [[arc]] is <math>\frac 23</math> of the [[right angle]]). Thus, the angle at each vertex is an [[inscribed angle]] subtending <math>60</math> degrees, making the answer <math>\frac 1260 = 30^{\circ} \Longrightarrow \mathrm{(C)}</math>
  
 
==See also==
 
==See also==
* [[2007 AMC 12A Problems/Problem 7 | Previous problem]]
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{{AMC12 box|year=2007|ab=A|num-b=7|num-a=9}}
* [[2007 AMC 12A Problems/Problem 9 | Next problem]]
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* [[2007 AMC 12A Problems]]
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[[Category:Introductory Geometry Problems]]

Revision as of 14:32, 9 September 2007

Problem

A star-polygon is drawn on a clock face by drawing a chord from each number to the fifth number counted clockwise from that number. That is, chords are drawn from 12 to 5, from 5 to 10, from 10 to 3, and so on, ending back at 12. What is the degree measure of the angle at each vertex in the star polygon?

$\mathrm{(A)}\ 20\qquad \mathrm{(B)}\ 24\qquad \mathrm{(C)}\ 30\qquad \mathrm{(D)}\ 36\qquad \mathrm{(E)}\ 60$

Solution

2007 AMC12A-8.png

We look at the angle between 12, 5, and 10. It subtends $\displaystyle \frac 16$ of the circle, or $60$ degrees (or you can see that the arc is $\frac 23$ of the right angle). Thus, the angle at each vertex is an inscribed angle subtending $60$ degrees, making the answer $\frac 1260 = 30^{\circ} \Longrightarrow \mathrm{(C)}$

See also

2007 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions