Difference between revisions of "2017 AMC 10A Problems/Problem 6"
(→Solution 2 (Elimination of Answer Choices)) |
(→Solution 2 (Elimination of Answer Choices)) |
||
Line 27: | Line 27: | ||
<math>\textbf{(C)}</math> False. There might be other sections as well. For example, his teacher can dictate that any student who answers all the Writing problems incorrectly will get an A. Or perhaps, a student who answers at least 5/8 of all questions correctly will receive an A. Or perhaps a student who draws a smiley face will receive an A. There may be many other ways to receive an A. | <math>\textbf{(C)}</math> False. There might be other sections as well. For example, his teacher can dictate that any student who answers all the Writing problems incorrectly will get an A. Or perhaps, a student who answers at least 5/8 of all questions correctly will receive an A. Or perhaps a student who draws a smiley face will receive an A. There may be many other ways to receive an A. | ||
− | <math>\textbf{(D)}</math> False. He might've | + | <math>\textbf{(D)}</math> False. He might've missed some number of multiple-choice section but still received an A using the example methods above or any other possible methods. |
<math>\textbf{(E)}</math> False. Lewis could have gotten 0 multiple-choice questions correct but still received an A using the example methods above or any other possible methods. | <math>\textbf{(E)}</math> False. Lewis could have gotten 0 multiple-choice questions correct but still received an A using the example methods above or any other possible methods. |
Revision as of 15:52, 23 July 2021
Contents
Problem
Ms. Carroll promised that anyone who got all the multiple choice questions right on the upcoming exam would receive an A on the exam. Which one of these statements necessarily follows logically?
Solution 1 (Using the Contrapositive)
Rewriting the given statement: "if someone got all the multiple choice questions right on the upcoming exam then he or she would receive an A on the exam." If that someone is Lewis the statement becomes: "if Lewis got all the multiple choice questions right, then he would receive an A on the exam."
The contrapositive: "If Lewis did not receive an A, then he did not get all of them right"
The contrapositive (in other words): "If Lewis did not get an A, then he got at least one of the multiple choice questions wrong".
B is also equivalent to the contrapositive of the original statement, which implies that it must be true, so the answer is .
- Note that answer choice (B) is the contrapositive of the given statement. (That is, it has been negated as well as reversed.) We know that the contrapositive is always true if the given statement is true.
~minor edits by BakedPotato66
Solution 2 (Elimination of Answer Choices)
False. If Lewis did not receive an A, that does not mean he got all the multiple-choice questions wrong. For example, he might have only gotten multiple-choice question wrong.
True. If Lewis got all the multiple-choice questions right, he would've gotten an A. If he didn't get an A, then he didn't get all of them right, since Lewis would have gotten an A if he got all the multiple-choice section right.
False. There might be other sections as well. For example, his teacher can dictate that any student who answers all the Writing problems incorrectly will get an A. Or perhaps, a student who answers at least 5/8 of all questions correctly will receive an A. Or perhaps a student who draws a smiley face will receive an A. There may be many other ways to receive an A.
False. He might've missed some number of multiple-choice section but still received an A using the example methods above or any other possible methods.
False. Lewis could have gotten 0 multiple-choice questions correct but still received an A using the example methods above or any other possible methods.
Therefore, our answer is
~minor edits by Terribleteeth
~edits by BakedPotato66
Video Solution
~savannahsolver
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.