Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"
(→See Also) |
|||
| Line 12: | Line 12: | ||
The factors of <math>27</math> are <math>1</math>, <math>3</math>, <math>9</math> and <math>27</math>. Out of these, only <math>3</math>, <math>9</math> and <math>27</math> are multiples of <math>3</math>, so the answer is <math>3 + 9 + 27 = \boxed{39}</math>. | The factors of <math>27</math> are <math>1</math>, <math>3</math>, <math>9</math> and <math>27</math>. Out of these, only <math>3</math>, <math>9</math> and <math>27</math> are multiples of <math>3</math>, so the answer is <math>3 + 9 + 27 = \boxed{39}</math>. | ||
| + | |||
| + | ==See also== | ||
| + | #[[2021 Accuracy Sprint Problems|Other 2021 JMPSC Sprint Problems]] | ||
| + | #[[2021 Accuracy Sprint Answer Key|2021 JMPSC Sprint Answer Key]] | ||
| + | #[[JMPSC Problems and Solutions|All JMPSC Problems and Solutions]] | ||
| + | {{JMPSC Notice}} | ||
Revision as of 16:20, 11 July 2021
Contents
Problem
Find the sum of all positive multiples of 
that are factors of 
Solution
We use the fact that 
and 
to conclude that the only multiples of that are factors of 
are , 
, and . Thus, our answer is 
.
~Bradygho
Solution 2
The factors of are 
, , and . Out of these, only , and are multiples of , so the answer is .
See also
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition. 
