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Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 6"
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We note that triangle <math>ABC</math> and <math>DAC</math> are congruent due to <math>AA</math> congruency. Therefore, <math>AD + DC = 28</math> and the perimeter of the quadrilateral is <math>28+28 = \boxed{56}</math>
 
We note that triangle <math>ABC</math> and <math>DAC</math> are congruent due to <math>AA</math> congruency. Therefore, <math>AD + DC = 28</math> and the perimeter of the quadrilateral is <math>28+28 = \boxed{56}</math>
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~Grisham

Revision as of 11:54, 11 July 2021

Problem

In quadrilateral $ABCD$, diagonal $\overline{AC}$ bisects both $\angle BAD$ and $\angle BCD$. If $AB=15$ and $BC=13$, find the perimeter of $ABCD$.

Solution

Notice that since $\overline{AC}$ bisects a pair of opposite angles in quadrilateral $ABCD$, we can distinguish this quadrilateral as a kite.

$\linebreak$ With this information, we have that $\overline{AD}=\overline{AB}=15$ and $\overline{CD}=\overline{BC}=13$.

Therefore, the perimeter is \[15+15+13+13=\boxed{56}\] $\square$

$\linebreak$ ~Apple321


Solution 2

We note that triangle $ABC$ and $DAC$ are congruent due to $AA$ congruency. Therefore, $AD + DC = 28$ and the perimeter of the quadrilateral is $28+28 = \boxed{56}$

~Grisham

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