Difference between revisions of "2021 GMC 10B"

Revision as of 00:21, 2 May 2021

What is $5!+3!-4!-2!+1!+0!?$

$\textbf{(A)} ~99 \qquad\textbf{(B)} ~100 \qquad\textbf{(C)} ~101 \qquad\textbf{(D)} ~102 \qquad\textbf{(E)} ~103$

The radius of a circle that has an area of $\frac{\pi}{\sqrt{2}}$ is $r$ . Find $r^{2}$

$\textbf{(A)} ~\frac{1}{2} \qquad\textbf{(B)} ~\frac{\sqrt{2}}{2} \qquad\textbf{(C)} ~\sqrt{2} \qquad\textbf{(D)} ~2 \qquad\textbf{(E)} ~4$

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 ==Problem 1==
-. What is <math>5!+3!-4!-2!+1!+0!?</math>
+What is <math>5!+3!-4!-2!+1!+0!?</math>
-<math>\textbf{(A)} ~31 \qquad\textbf{(B)} ~32 \qquad\textbf{(C)} ~33 \qquad\textbf{(D)} ~34 \qquad\textbf{(E)} ~35 </math>
+<math>\textbf{(A)} ~99 \qquad\textbf{(B)} ~100 \qquad\textbf{(C)} ~101 \qquad\textbf{(D)} ~102 \qquad\textbf{(E)} ~103 </math>
+==Problem 2==
+The radius of a circle that has an area of <math>\frac{\pi}{\sqrt{2}}</math> is <math>r</math>. Find <math>r^{2}</math>
+<math>\textbf{(A)} ~\frac{1}{2} \qquad\textbf{(B)} ~\frac{\sqrt{2}}{2} \qquad\textbf{(C)} ~\sqrt{2} \qquad\textbf{(D)} ~2 \qquad\textbf{(E)} ~4 </math>