Difference between revisions of "2021 AIME II Problems/Problem 1"
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==Solution 2 (Symmetry)== | ==Solution 2 (Symmetry)== | ||
| − | For any palindrome <math>ABA,</math> note that | + | For any palindrome <math>ABA,</math> note that <math>ABA,</math> is 100A + 10b + A which is also 101A + 10B. |
<b>Will finish up soon. No edit please. Thanks. | <b>Will finish up soon. No edit please. Thanks. | ||
Revision as of 15:03, 22 March 2021
Problem
Find the arithmetic mean of all the three-digit palindromes. (Recall that a palindrome is a number that reads the same forward and backward, such as 
or 
.)
Solution 1
Recall the the arithmetic mean of all the 
digit palindromes is just the average of the largest and smallest digit palindromes, and in this case the 
palindromes are 
and 
and 
and 
is the final answer.
~ math31415926535
Solution 2 (Symmetry)
For any palindrome 
note that is 100A + 10b + A which is also 101A + 10B.
Will finish up soon. No edit please. Thanks.
~MRENTHUSIASM
See also
| 2021 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
