Difference between revisions of "Fundamental Theorem of Sato"
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The Fundamental Theorem of Sato states the following: | The Fundamental Theorem of Sato states the following: | ||
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Method 4: Proof by Gmass | Method 4: Proof by Gmass | ||
− | Gmass is Sato in cat form. Since Gmass is amazing, and since if <math>a=b</math> and <math>b=c</math>, <math>a=c</math>, Sato is amazing. | + | Gmass is Sato in cat form. Since Gmass is amazing, and since if <math>a=b</math> and <math>b=c</math>, <math>a=c</math>, Sato is amazing.(Proved) |
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+ | Method 5: Proof by oof | ||
+ | Sato knows the way of the oof. He knows how to oof every single problem given. Not even Gmaas can use the way of the oof, as Gmaas is too puny to know the way of the oof. Therefore, Sato is amazing. (Proved) | ||
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Revision as of 17:24, 16 March 2021
The Fundamental Theorem of Sato states the following:
Sato is amazing.
Proof:
Method 1: Proof by Contradiction
Assume, for contradiction, that Sato is not amazing.
This is absurd. Therefore, Sato is amazing. (Proved)
Method 2: Proof by Authority
Whatever AoPS says is correct, and AoPS says that Mr. Sato is amazing. Thus, Mr. Sato is amazing. (Proved)
Method 3: Proof by Pigeonhole
There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
Method 4: Proof by Gmass
Gmass is Sato in cat form. Since Gmass is amazing, and since if and , , Sato is amazing.(Proved)
Method 5: Proof by oof
Sato knows the way of the oof. He knows how to oof every single problem given. Not even Gmaas can use the way of the oof, as Gmaas is too puny to know the way of the oof. Therefore, Sato is amazing. (Proved)
Learn about Sato: https://artofproblemsolving.com/wiki/index.php/Naoki_Sato
Back to Main Page: https://artofproblemsolving.com/wiki/index.php/Main_Page