Difference between revisions of "2021 AMC 12A Problems/Problem 4"

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{{duplicate|[[2021 AMC 10A Problems#Problem 7|2021 AMC 10A #7]] and [[2021 AMC 12A Problems#Problem 4|2021 AMC 12A #4]]}}
 
{{duplicate|[[2021 AMC 10A Problems#Problem 7|2021 AMC 10A #7]] and [[2021 AMC 12A Problems#Problem 4|2021 AMC 12A #4]]}}
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==Simple and Quick Video Solution==
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https://youtu.be/hJKHaIcyIxA
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Education the Study of Everything
  
 
==Problem==
 
==Problem==
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<math>\textbf{(E) }</math> Happy snakes can't subtract.
 
<math>\textbf{(E) }</math> Happy snakes can't subtract.
 
  
 
==Solution 1==
 
==Solution 1==

Revision as of 15:15, 15 February 2021

The following problem is from both the 2021 AMC 10A #7 and 2021 AMC 12A #4, so both problems redirect to this page.

Simple and Quick Video Solution

https://youtu.be/hJKHaIcyIxA

Education the Study of Everything

Problem

Tom has a collection of $13$ snakes, $4$ of which are purple and $5$ of which are happy. He observes that all of his happy snakes can add, none of his purple snakes can subtract, and all of his snakes that can't subtract also can't add. Which of these conclusions can be drawn about Tom's snakes?

$\textbf{(A) }$ Purple snakes can add.

$\textbf{(B) }$ Purple snakes are happy.

$\textbf{(C) }$ Snakes that can add are purple.

$\textbf{(D) }$ Happy snakes are not purple.

$\textbf{(E) }$ Happy snakes can't subtract.

Solution 1

We know that purple snakes cannot subtract, thus they cannot add either. Since happy snakes must be able to add, the purple snakes cannot be happy. Therefore, we know that the happy snakes are not purple and the answer is $\boxed{\textbf{(D)}}$.

--abhinavg0627

Solution 2 (Explains Solution 1 Using Arrows)

We are given that

$\text{(1) Happy}\Rightarrow\text{can add}$

$\text{(2) Purple}\Rightarrow\text{cannot subtract}$

$\text{(3) Cannot subtract}\Rightarrow\text{cannot add}$

Combining $\text{(2)}$ and $\text{(3)}$ into $\text{(*)}$ below, we have

$\text{(1) Happy}\Rightarrow\text{can add}$

$\text{(*) Purple}\Rightarrow\text{cannot subtract}\Rightarrow\text{cannot add}$

Clearly, the answer is $\boxed{\textbf{(D)}}.$

~MRENTHUSIASM

Video Solution by Aaron He (Sets)

https://www.youtube.com/watch?v=xTGDKBthWsw&t=164

Video Solution by Punxsutawney Phil

https://youtube.com/watch?v=MUHja8TpKGw&t=259s (Note that there's a slight error in the video I corrected in the description)

Video Solution by Hawk Math

https://www.youtube.com/watch?v=P5al76DxyHY

Video Solution (Using logic to eliminate choices)

https://youtu.be/Mofw3VXHPyg

~ pi_is_3.14

See also

2021 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
2021 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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