Difference between revisions of "1956 AHSME Problems/Problem 5"

(Created page with "== Problem #5== A nickel is placed on a table. The number of nickels which can be placed around it, each tangent to it and to two others is: <math>\textbf{(A)}\ 4 \qquad\tex...")
 
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<math>\textbf{(A)}\ 4 \qquad\textbf{(B)}\ 5 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 8 \qquad\textbf{(E)}\ 12</math>
 
<math>\textbf{(A)}\ 4 \qquad\textbf{(B)}\ 5 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 8 \qquad\textbf{(E)}\ 12</math>
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==Solution==
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Arrange the nickels in a hexagonal fashion. One can see that one can only place <math>\boxed{\textbf{(C)} \quad 6}</math> nickels around the central nickel.
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==See Also==
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{{AHSME box|year=1956|num-b=4|num-a=6}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Revision as of 20:18, 12 February 2021

Problem #5

A nickel is placed on a table. The number of nickels which can be placed around it, each tangent to it and to two others is:

$\textbf{(A)}\ 4 \qquad\textbf{(B)}\ 5 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 8 \qquad\textbf{(E)}\ 12$

Solution

Arrange the nickels in a hexagonal fashion. One can see that one can only place $\boxed{\textbf{(C)} \quad 6}$ nickels around the central nickel.

See Also

1956 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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