Difference between revisions of "2020 AMC 10A Problems/Problem 2"
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− | ==Video | + | ==Video Solution 2== |
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~IceMatrix | ~IceMatrix | ||
+ | ==Video Solution 3== | ||
https://www.youtube.com/watch?v=7-3sl1pSojc | https://www.youtube.com/watch?v=7-3sl1pSojc | ||
~bobthefam | ~bobthefam | ||
+ | ==Video Solution 4== | ||
https://youtu.be/zVppmKOvx_w | https://youtu.be/zVppmKOvx_w | ||
Revision as of 13:24, 22 December 2020
Contents
Problem
The numbers and have an average (arithmetic mean) of . What is the average of and ?
Solution
The arithmetic mean of the numbers and is equal to . Solving for , we get . Dividing by to find the average of the two numbers and gives .
Video Solution 1
Education, The Study of Everything
Video Solution 2
~IceMatrix
Video Solution 3
https://www.youtube.com/watch?v=7-3sl1pSojc
~bobthefam
Video Solution 4
~savannahsolver
See Also
2020 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.