Difference between revisions of "2020 AIME II Problems/Problem 1"
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==Purple Comet Math Meet April 2020== | ==Purple Comet Math Meet April 2020== | ||
− | Notice, that this was the exact same problem (with different wording of course) as Purple Comet HS problem 3 and remembering the answer, put <math>\boxed{ | + | Notice, that this was the exact same problem (with different wording of course) as Purple Comet HS problem 3 and remembering the answer, put <math>\boxed{231}</math>. |
https://purplecomet.org/views/data/2020HSSolutions.pdf | https://purplecomet.org/views/data/2020HSSolutions.pdf |
Revision as of 20:44, 28 November 2020
Contents
Problem
Find the number of ordered pairs of positive integers such that .
Solution
First, we find the prime factorization of , which is . The equation tells us that we want to select a perfect square factor of , . The might throw you off here, but it's actually kind of irrelevant because once is selected, the remaining factor will already be assigned as . There are ways to select a perfect square factor of , thus our answer is .
~superagh
Solution 2 (Official MAA)
Because , if , there must be nonnegative integers , , , and such that and . Then and The first equation has solutions corresponding to , and the second equation has solutions corresponding to . Therefore there are a total of ordered pairs such that .
Video Solution
https://www.youtube.com/watch?v=x0QznvXcwHY
~IceMatrix
Video Solution 2
~avn
Purple Comet Math Meet April 2020
Notice, that this was the exact same problem (with different wording of course) as Purple Comet HS problem 3 and remembering the answer, put .
https://purplecomet.org/views/data/2020HSSolutions.pdf
~Lopkiloinm
See Also
2020 AIME II (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.