Difference between revisions of "2020 AMC 8 Problems/Problem 21"
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<math>\textbf{(A) }28 \qquad \textbf{(B) }30 \qquad \textbf{(C) }32 \qquad \textbf{(D) }33 \qquad \textbf{(E) }35</math> | <math>\textbf{(A) }28 \qquad \textbf{(B) }30 \qquad \textbf{(C) }32 \qquad \textbf{(D) }33 \qquad \textbf{(E) }35</math> | ||
+ | |||
+ | |||
+ | ==Solution== | ||
+ | We count paths. Noticing that we can only go along white squares, to get to a white square we can only go from the two whites beneath it. Here is a diagram: | ||
+ | <asy> | ||
+ | int N = 7; | ||
+ | for (int i = 0; i < 8; ++i) { | ||
+ | for (int j = 0; j < 8; ++j) { | ||
+ | draw((i,j)--(i+1,j)--(i+1,j+1)--(i,j+1)--(i,j)); | ||
+ | if ((i+j) % 2 == 0) { | ||
+ | filldraw((i,j)--(i+1,j)--(i+1,j+1)--(i,j+1)--(i,j)--cycle,black); | ||
+ | } | ||
+ | } | ||
+ | } | ||
+ | label("$1$", (5.5, .5)); | ||
+ | label("$1$", (4.5, 1.5)); | ||
+ | label("$1$", (6.5, 1.5)); | ||
+ | label("$1$", (3.5, 2.5)); | ||
+ | label("$1$", (7.5, 2.5)); | ||
+ | label("$2$", (5.5, 2.5)); | ||
+ | label("$1$", (2.5, 3.5)); | ||
+ | label("$3$", (6.5, 3.5)); | ||
+ | label("$3$", (4.5, 3.5)); | ||
+ | label("$4$", (3.5, 4.5)); | ||
+ | label("$3$", (7.5, 4.5)); | ||
+ | label("$6$", (5.5, 4.5)); | ||
+ | label("$10$", (4.5, 5.5)); | ||
+ | label("$9$", (6.5, 5.5)); | ||
+ | label("$19$", (5.5, 6.5)); | ||
+ | label("$9$", (7.5, 6.5)); | ||
+ | label("$\boxed{\textbf{(A)}28}$", (6.5, 7.5)); | ||
+ | </asy> | ||
+ | |||
+ | ~yofro (Diagram credits to franzliszt) | ||
==See also== | ==See also== | ||
{{AMC8 box|year=2020|num-b=20|num-a=22}} | {{AMC8 box|year=2020|num-b=20|num-a=22}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 01:27, 18 November 2020
Problem 21
A game board consists of squares that alternate in color between black and white. The figure below shows square in the bottom row and square in the top row. A marker is placed at A step consists of moving the marker onto one of the adjoining white squares in the row above. How many -step paths are there from to (The figure shows a sample path.)
Solution
We count paths. Noticing that we can only go along white squares, to get to a white square we can only go from the two whites beneath it. Here is a diagram:
int N = 7; for (int i = 0; i < 8; ++i) { for (int j = 0; j < 8; ++j) { draw((i,j)--(i+1,j)--(i+1,j+1)--(i,j+1)--(i,j)); if ((i+j) % 2 == 0) { filldraw((i,j)--(i+1,j)--(i+1,j+1)--(i,j+1)--(i,j)--cycle,black); } } } label("$1$", (5.5, .5)); label("$1$", (4.5, 1.5)); label("$1$", (6.5, 1.5)); label("$1$", (3.5, 2.5)); label("$1$", (7.5, 2.5)); label("$2$", (5.5, 2.5)); label("$1$", (2.5, 3.5)); label("$3$", (6.5, 3.5)); label("$3$", (4.5, 3.5)); label("$4$", (3.5, 4.5)); label("$3$", (7.5, 4.5)); label("$6$", (5.5, 4.5)); label("$10$", (4.5, 5.5)); label("$9$", (6.5, 5.5)); label("$19$", (5.5, 6.5)); label("$9$", (7.5, 6.5)); label("$\boxed{\textbf{(A)}28}$", (6.5, 7.5)); (Error making remote request. Unknown error_msg)
~yofro (Diagram credits to franzliszt)
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 20 |
Followed by Problem 22 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.