Difference between revisions of "2019 AMC 10A Problems/Problem 1"
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| − | ==Problem | + | == Problem == |
What is the value of <cmath>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?</cmath> | What is the value of <cmath>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?</cmath> | ||
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<math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math> | <math>\textbf{(A) } 0 \qquad\textbf{(B) } 1 \qquad\textbf{(C) } 2 \qquad\textbf{(D) } 3 \qquad\textbf{(E) } 4</math> | ||
== Solution == | == Solution == | ||
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<math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9</math> | <math>2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9</math> | ||
<math>= 1+1 = \boxed{2}</math> which corresponds to <math>\boxed{\text{C}}</math>. | <math>= 1+1 = \boxed{2}</math> which corresponds to <math>\boxed{\text{C}}</math>. | ||
| − | ==Video Solution== | + | == Video Solution == |
https://youtu.be/Ad8WKcwZcTA | https://youtu.be/Ad8WKcwZcTA | ||
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== See Also == | == See Also == | ||
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{{AMC10 box|year=2019|ab=A|before=First Problem|num-a=2}} | {{AMC10 box|year=2019|ab=A|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:45, 19 October 2020
Contents
Problem
What is the value of ![\[2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?\]](http://latex.artofproblemsolving.com/6/7/6/67606c2b8141058216ca18ee5e71821458b74b01.png)
Solution
which corresponds to 
.
Video Solution
~savannahsolver
See Also
| 2019 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
