Difference between revisions of "2003 AMC 10A Problems/Problem 2"
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Since <math>2366</math> dollars was the cost for the club, and <math>26</math> was the cost per member, the number of members in the League is <math>\frac{2366}{26}=91 \Rightarrow B</math>. | Since <math>2366</math> dollars was the cost for the club, and <math>26</math> was the cost per member, the number of members in the League is <math>\frac{2366}{26}=91 \Rightarrow B</math>. | ||
| − | == See | + | == See also == |
| − | + | {{AMC10 box|year=2003|ab=A|num-b=1|num-a=2}} | |
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[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
Revision as of 16:31, 26 February 2007
Problem
Members of the Rockham Soccer League buy socks and T-shirts. Socks cost $4 per pair and each T-shirt costs $5 more than a pair of socks. Each member needs one pair of socks and a shirt for home games and another pair of socks and a shirt for away games. If the total cost is $2366, how many members are in the League?
Solution
Since T-shirts cost 
dollars more than a pair of socks, T-shirts cost 
dollars.
Since each member needs 
pairs of socks and T-shirts, the total cost for 
member is 
dollars.
Since 
dollars was the cost for the club, and 
was the cost per member, the number of members in the League is 
.
See also
| 2003 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
