Difference between revisions of "2017 AMC 10A Problems/Problem 1"
m |
m (Minor LaTeX formats) |
||
Line 10: | Line 10: | ||
Notice this is the term <math>a_6</math> in a recursive sequence, defined recursively as <math>a_1 = 3, a_n = 2a_{n-1} + 1.</math> Thus: | Notice this is the term <math>a_6</math> in a recursive sequence, defined recursively as <math>a_1 = 3, a_n = 2a_{n-1} + 1.</math> Thus: | ||
<cmath>\begin{split} | <cmath>\begin{split} | ||
− | a_2 = 3 | + | a_2 = 3 \cdot 2 + 1 = 7.\\ |
− | a_3 = 7 | + | a_3 = 7 \cdot 2 + 1 = 15.\\ |
− | a_4 = 15 | + | a_4 = 15 \cdot 2 + 1 = 31.\\ |
− | a_5 = 31 | + | a_5 = 31 \cdot 2 + 1 = 63.\\ |
− | a_6 = 63 | + | a_6 = 63 \cdot 2 + 1 = \boxed{\textbf{(C)}\ 127} |
\end{split}</cmath>. | \end{split}</cmath>. | ||
+ | |||
+ | Minor LaTeX edits by fasterthanlight | ||
== Solution 2 == | == Solution 2 == |
Revision as of 09:33, 28 May 2020
Problem
What is the value of ?
Solution 1
Notice this is the term in a recursive sequence, defined recursively as Thus: .
Minor LaTeX edits by fasterthanlight
Solution 2
Starting to compute the inner expressions, we see the results are . This is always less than a power of . The only admissible answer choice by this rule is thus .
Solution 3
Working our way from the innermost parenthesis outwards and directly computing, we have .
Solution 4
If you distribute this you get a sum of the powers of . The largest power of in the series is , so the sum is .
Video Solution
See Also
2017 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.