Difference between revisions of "1981 AHSME Problems/Problem 21"
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In a triangle with sides of lengths <math>a</math>, <math>b</math>, and <math>c</math>, <math>(a+b+c)(a+b-c) = 3ab</math>. The measure of the angle opposite the side length <math>c</math> is | In a triangle with sides of lengths <math>a</math>, <math>b</math>, and <math>c</math>, <math>(a+b+c)(a+b-c) = 3ab</math>. The measure of the angle opposite the side length <math>c</math> is | ||
<math>\textbf{(A)}\ 15^\circ\qquad\textbf{(B)}\ 30^\circ\qquad\textbf{(C)}\ 45^\circ\qquad\textbf{(D)}\ 60^\circ\qquad\textbf{(E)}\ 150^\circ</math> | <math>\textbf{(A)}\ 15^\circ\qquad\textbf{(B)}\ 30^\circ\qquad\textbf{(C)}\ 45^\circ\qquad\textbf{(D)}\ 60^\circ\qquad\textbf{(E)}\ 150^\circ</math> | ||
Revision as of 14:33, 6 March 2020
Problem 21
In a triangle with sides of lengths 
, 
, and 
, 
. The measure of the angle opposite the side length is
