Difference between revisions of "Derangement"

Line 1: Line 1:
 
A '''derangement''' is a [[permutation]] with no [[fixed point]]s.  A derangement can also be thought of as a permutation in which none of the objects are in their original space.  For example, the derangements of <math>(1,2,3)</math> are <math>(2, 3, 1)</math> and <math>(3, 1, 2)</math>.  The number of derangements of a set of x objects is denoted !x, and is given by the formula:
 
A '''derangement''' is a [[permutation]] with no [[fixed point]]s.  A derangement can also be thought of as a permutation in which none of the objects are in their original space.  For example, the derangements of <math>(1,2,3)</math> are <math>(2, 3, 1)</math> and <math>(3, 1, 2)</math>.  The number of derangements of a set of x objects is denoted !x, and is given by the formula:
 +
 +
  
 
<math>\displaystyle !x = x! \sum_{k=1}^{n} \frac{-1^k}{k!}</math>
 
<math>\displaystyle !x = x! \sum_{k=1}^{n} \frac{-1^k}{k!}</math>
 +
 +
  
 
{{stub}}
 
{{stub}}

Revision as of 16:15, 13 November 2006

A derangement is a permutation with no fixed points. A derangement can also be thought of as a permutation in which none of the objects are in their original space. For example, the derangements of $(1,2,3)$ are $(2, 3, 1)$ and $(3, 1, 2)$. The number of derangements of a set of x objects is denoted !x, and is given by the formula:


$\displaystyle !x = x! \sum_{k=1}^{n} \frac{-1^k}{k!}$


This article is a stub. Help us out by expanding it.