Difference between revisions of "2020 AMC 10B Problems/Problem 1"
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The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> ~quacker88 | The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> ~quacker88 | ||
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==Video Solution== | ==Video Solution== | ||
https://youtu.be/Gkm5rU5MlOU | https://youtu.be/Gkm5rU5MlOU | ||
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~IceMatrix | ~IceMatrix | ||
| − | = See Also = | + | ==See Also== |
{{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}} | {{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:46, 7 February 2020
Contents
Problem
What is the value of
![\[1-(-2)-3-(-4)-5-(-6)?\]](http://latex.artofproblemsolving.com/9/4/c/94cdfebdc087637cc5450da458e0db822c81da88.png)
Solution
We know that when we subtract negative numbers, 
.
The equation becomes 
~quacker88
Video Solution
~IceMatrix
See Also
| 2020 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
