Difference between revisions of "2020 AMC 10B Problems/Problem 2"

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<math>5+40=\boxed{\textbf{(E) }21}</math> ~quacker88
 
<math>5+40=\boxed{\textbf{(E) }21}</math> ~quacker88
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==See Also==
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{{AMC12 box|year=2020|ab=B|num-b=1|num-a=3}}
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{{MAA Notice}}

Revision as of 15:34, 7 February 2020

Problem

What is the value of \[1-(-2)-3-(-4)-5-(-6)?\]

$\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\  3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21$

Solution

A cube with side length $1$ has volume $1^3=1$, so $5$ of these will have a total volume of $5\cdot1=5$.

A cube with side length $2$ has volume $2^3=8$, so $5$ of these will have a total volume of $5\cdot8=40$.

$5+40=\boxed{\textbf{(E) }21}$ ~quacker88

See Also

2020 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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