Difference between revisions of "2020 AMC 10B Problems/Problem 1"
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− | ==Problem | + | ==Problem== |
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− | <math>\textbf{(A)}\ \qquad\textbf{(B)}\ \qquad\textbf{(C)}\ \qquad\textbf{(D)}\ \qquad\textbf{(E)}\ </math> | + | What is the value of |
+ | <cmath>1-(-2)-3-(-4)-5-(-6)?</cmath> | ||
+ | |||
+ | <math>\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21</math> | ||
+ | |||
+ | ==Solution== | ||
+ | We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>. | ||
+ | |||
+ | The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> | ||
== Solution == | == Solution == |
Revision as of 15:25, 7 February 2020
Problem
What is the value of
Solution
We know that when we subtract negative numbers, .
The equation becomes
Solution
Solution
Video Solution
YouTube Link
See Also
2020 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
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All AMC 10 Problems and Solutions |
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