Difference between revisions of "1953 AHSME Problems/Problem 40"

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Solution by <math>\underline{\textbf{Invoker}}</math>
 
Solution by <math>\underline{\textbf{Invoker}}</math>
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==See Also==
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{{AHSME 50p box|year=1953|num-b=39|num-a=41}}
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{{MAA Notice}}

Revision as of 00:46, 4 February 2020

Problem

The negation of the statement "all men are honest," is:

$\textbf{(A)}\ \text{no men are honest} \qquad \textbf{(B)}\ \text{all men are dishonest} \\  \textbf{(C)}\ \text{some men are dishonest}\qquad \textbf{(D)}\ \text{no men are dishonest}\\ \textbf{(E)}\ \text{some men are honest}$

Solution

This statement can also be written as "If someone is a man, then they are honest."

The negation of this statement is "If someone is a man, then they are not honest."

The statement that means the same as the statement above is $\boxed{\textbf{(B)} \text{all men are dishonest}}$

Solution by $\underline{\textbf{Invoker}}$

See Also

1953 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 39
Followed by
Problem 41
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All AHSME Problems and Solutions


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