Difference between revisions of "2008 AMC 8 Problems/Problem 19"
Karthic7073 (talk | contribs) m (→See Also) |
Shurong.ge (talk | contribs) (→Solution 1) |
||
| Line 15: | Line 15: | ||
==Solution 1== | ==Solution 1== | ||
| − | The two points are one unit apart at <math>8</math> places around the edge of the square. There are <math> | + | The two points are one unit apart at <math>8</math> places around the edge of the square. There are <math>8 \choose 2</math><math> = 28</math> ways to choose two points. The probability is |
<cmath>\frac{8}{28} = \boxed{\textbf{(B)}\ \frac27}</cmath> | <cmath>\frac{8}{28} = \boxed{\textbf{(B)}\ \frac27}</cmath> | ||
Revision as of 23:22, 7 January 2020
Contents
Problem
Eight points are spaced around at intervals of one unit around a 
square, as shown. Two of the 
points are chosen at random. What is the probability that the two points are one unit apart?
![[asy] size((50)); dot((5,0)); dot((5,5)); dot((0,5)); dot((-5,5)); dot((-5,0)); dot((-5,-5)); dot((0,-5)); dot((5,-5)); [/asy]](http://latex.artofproblemsolving.com/7/b/4/7b4e4d5204c427f5ab2b242c550558317658b12d.png)
Solution 1
The two points are one unit apart at places around the edge of the square. There are 
ways to choose two points. The probability is
![\[\frac{8}{28} = \boxed{\textbf{(B)}\ \frac27}\]](http://latex.artofproblemsolving.com/2/d/8/2d8bb743056c3f8a324def77999d5c702eb2113a.png)
Solution 2
Arbitrarily pick a point in the grid. Clearly, we see two options for the other point to be placed, so the answer is 
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 18 |
Followed by Problem 20 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
