Difference between revisions of "2016 AMC 8 Problems/Problem 1"
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It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is <math>60</math> minutes in a hour. Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours. Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>. | It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is <math>60</math> minutes in a hour. Therefore, there are <math>11 \cdot 60 = 660</math> minutes in 11 hours. Adding the second part(the 5 minutes) we get <math>660 + 5 = \boxed{\textbf{(C)}\ 665}</math>. | ||
| + | ==Solution 2== | ||
| + | The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of <math>665</math>. | ||
{{AMC8 box|year=2016|before=First Problem|num-a=2}} | {{AMC8 box|year=2016|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 15:57, 12 November 2019
The longest professional tennis match ever played lasted a total of 
hours and 
minutes. How many minutes was this?
Solution
It is best to split 11 hours and 5 minutes into 2 parts, one of 11 hours and another of 5 minutes. We know that there is 
minutes in a hour. Therefore, there are 
minutes in 11 hours. Adding the second part(the 5 minutes) we get 
.
Solution 2
The best method comes when you remember your multiplication tables. Thus trivial, we get our answer of 
.
| 2016 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
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| All AJHSME/AMC 8 Problems and Solutions | ||
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