Difference between revisions of "1981 AHSME Problems/Problem 1"

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==Problem==
 
If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals:
 
If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals:
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<math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math>
 
<math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math>
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==Solution==
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<math>\boxed{\textbf{(E) }16}</math>

Revision as of 14:00, 24 March 2019

Problem

If $\sqrt{x+2}=2$, then $(x+2)^2$ equals:

$\textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16$


Solution

$\boxed{\textbf{(E) }16}$