Difference between revisions of "2019 AIME I Problems/Problem 1"
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==Problem 1== | ==Problem 1== | ||
What is the sum of the digits of <math>9+99+999+...+99..99</math> (321 9's)? | What is the sum of the digits of <math>9+99+999+...+99..99</math> (321 9's)? | ||
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| + | ==Solution== | ||
{{AIME box|year=2019|n=I|before=First Problem|num-a=2}} | {{AIME box|year=2019|n=I|before=First Problem|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 21:21, 14 March 2019
Problem 1
What is the sum of the digits of 
(321 9's)?
Solution
| 2019 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
