Difference between revisions of "2019 AMC 10B Problems/Problem 11"

Revision as of 03:31, 17 February 2019

Problem

Two jars each contain the same number of marbles, and every marble is either blue or green. In Jar 1 the ratio of blue to green marbles is 9:1, and the ratio of blue to green marbles in Jar 2 is 8:1. There are 95 green marbles in all. How many more blue marbles are in Jar 1 than in Jar 2?

$\textbf{(A) } 5\qquad\textbf{(B) } 10 \qquad\textbf{(C) }25 \qquad\textbf{(D) } 45 \qquad \textbf{(E) } 50$

Solution

Call the amount of marbles in each jar $x$ , because they are equivalent. Thus, $\frac{x}{10}$ is the amount of green marbles in $1$ , and $\frac{x}{9}$ is the amount of green marbles in $2$ . $\frac{x}{9}+\frac{x}{10}=\frac{19x}{90}$ , $\frac{19x}{90}=95$ , and $x=450$ marbles in each jar. Because the $\frac{9x}{10}$ is the amount of blue marbles in jar $1$ , and $\frac{8x}{9}$ is the amount of blue marbles in jar $2$ , $\frac{9x}{10}-\frac{8x}{9}=\frac{x}{90}$ , so there must be $5$ more marbles in jar $1$ than jar $2$ . The answer is $\boxed{A}$

2019 AMC 10B (Problems • Answer Key • Resources)
Preceded by Problem 10	Followed by Problem 12
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The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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Difference between revisions of "2019 AMC 10B Problems/Problem 11"

Revision as of 03:31, 17 February 2019

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Solution

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