Difference between revisions of "2019 AMC 12B Problems/Problem 3"
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==Solution== | ==Solution== | ||
| − | We can simply graph or use coordinate rules to realize that both <math>A</math> and <math>B</math> are rotated <math>180^{\circ}</math> about the origin, therefore <math>\overline{AB}</math> is rotated <math>180^{\circ}</math>, so <math>\boxed{(\text{E})}</math> | + | We can simply graph or use coordinate rules to realize that both <math>A</math> and <math>B</math> are rotated <math>180^{\circ}</math> about the origin, therefore <math>\overline{AB}</math> is rotated <math>180^{\circ}</math>, so <math>\boxed{(\text{E})}</math> -Dodgers66 |
==See Also== | ==See Also== | ||
{{AMC12 box|year=2019|ab=B|num-b=2|num-a=4}} | {{AMC12 box|year=2019|ab=B|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 14:38, 14 February 2019
Problem
Which of the following rigid transformations (isometries) maps the line segment 
onto the line segment 
so that the image of 
is 
and the image of 
is 
?
reflection in the 
-axis
counterclockwise rotation around the origin by 
translation by 3 units to the right and 5 units down
reflection in the 
-axis
clockwise rotation about the origin by 
Solution
We can simply graph or use coordinate rules to realize that both 
and 
are rotated about the origin, therefore is rotated , so 
-Dodgers66
See Also
| 2019 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 2 |
Followed by Problem 4 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
