Difference between revisions of "2019 AMC 12B Problems/Problem 7"

Line 6: Line 6:
 
==See Also==
 
==See Also==
 
{{AMC12 box|year=2019|ab=B|num-b=6|num-a=8}}
 
{{AMC12 box|year=2019|ab=B|num-b=6|num-a=8}}
 +
{{MAA Notice}}

Revision as of 11:25, 14 February 2019

Problem

Solution

$\boxed{-5}$ if my memory isn't trash

See Also

2019 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png